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Calculations

From: ken rauen
To: Sterling D. Allan
Sent: Thursday, June 24, 2004 4:52 PM
Subject: Re: ... Telesis Site ...

Hi Sterling and Friends,

[..na..]

One inch-pound of work is 0.011 Joules. A 4x value per revolution is 0.044 J. At 1000 rpm, the maximum operation expected (and I agree), this is merely 0.73 Watts.

[..na..]

Ken
[Science Advisor, PES]

Richard's Reply

From: Richard
To: sterlingda@greaterthings.c*
Sent: Thursday, June 24, 2004 8:54 PM
Subject: Liquid NItrogen power Gobble fix.

Sterling,
[..na..]
Ken's exact numbers on power output could be low, if this is producing a net gain of 1 to 1.5 inch lbs. per revolution at 1000 rpm 's
it will produce between 16,000 and 24,000 inch ounces per minute.
SAY 24,000 divided by 16 and then divide it by 850 then you have approx. Horsepower might be about 1.7647.
I am not sure but I think those are pretty close numbers. I may have to divide these numbers per second to come up with a #
that is actual Horsepower.

Thanks, Richard

------

From: Richard
To: sterlingda@greaterthings.c*
Sent: Thursday, June 24, 2004 9:07 PM
Subject: More accurate HP numbers.

Sterling,
If this device turns at 1000 rpm 's at 1.5 inch pounds per revolution.
That is 16.66 revolution per second.
Take 24 inch ounce and multiply that by 16.66 and you get 399.99 inch ounces divide by 16 and then by 850 and
this would produce a constant 0.0294 Horsepower.
This is a more accurate number than sent in previous e-mail.

I look forward to your reply
Thanks,
Richard Timko

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Math Needs Work

From: ken rauen 
Sent: Friday, June 25, 2004 11:12 AM
Subject: Re: [pes_e-admin] Fw: Calculations from Coversion Website

One inch-pound is 0.083 foot-pound. (1 in # = 0.73 Ws)(0.083 ft # / in #) = 0.061 ft #. Richard, you are way off. Show your math.

Ken
[PES Science Advisor]

* * * *

Engineer Input

From: [A., Engineer]
To: richard
Cc: Sterling D. Allan
Sent: Friday, June 25, 2004 2:14 AM
Subject: Power calculation

Richard,
Before multiplying by torque to get power, it is necessary to convert RPM (revolutions/minute) to rad/min (radians/minute).

Since 1 revolution = 2*pi rad (Note 3)
= 2*3.14 rad (approx.)
= 6.28 rad,

that means 1000 rev/min = 6.28*1000 rad/min
= 6,280 rad/min.

For the power calculation, IF you have a constant 24 in-oz of torque throughout the complete 360 degree rotation (note 1), and IF you have that torque while running at 1000 RPM (note 2),
then 24 in-oz * 6,280 rad/min = 150,720 in-oz/min (shaft power at 1000 RPM)
= 2,512 in-oz/sec (min = 60 sec)
= 157 in-lb/sec (lb = 16 oz)
= 13.083 ft-lb/sec (ft = 12 in) (Note 3)
= 0.02378 hp (hp = 550 ft-lb/sec)
= 17.74 Watts (hp = 745.7 Watts)
= 5.199 BTU/hr (BTU/hour = 3.4121 Watts) (Note 4)


Note 1: It is not likely that the torque is constant throughout the whole rotation.
Note 2: Generally, torque changes with speed. You need a dynamometer or a pony brake.
Note 3: "pi" is the ratio of circumference to diameter of any circle, pi = 3.14159...
Note 4: BTUs are heat energy, and BTU/hour is heat flow

I hope these calculations are useful to you.

Regards,
[A., PES Engineer]

* * * *

I Concur with A.'s Calculations

See also

• Data

Page posted by SDA June 25, 2004
Last updated June 26, 2004

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